Solve Quadratic Equation: Find x, Show 2x2+11x-35=0

[Gringo123]

I have been working on a 2-part question which involves a diagram of a triangle ABC.
side AC = (2x + 1)
side BC = (x + 5)
angle C = 30⁰
the area of the triangle = 10 cm²

Question 1
Find the value of x
I have done that using the quadratic formula ( x = 2.26)

Question 2
Show that: 2x² + 11^x - 35 = 0

I do not understabnd exactly what I am being asked to do in Qu. 2 and how would I go about answering the question?

 

[HallsofIvy]

I have been working on a 2-part question which involves a diagram of a triangle ABC.
side AC = (2x + 1)
side BC = (x + 5)
angle C = 30⁰
the area of the triangle = 10 cm²

Question 1
Find the value of x
I have done that using the quadratic formula ( x = 2.26)

Using the quadratic formula on what equation? That is NOT what I got.

Question 2
Show that: 2x² + 11^x - 35 = 0

I do not understabnd exactly what I am being asked to do in Qu. 2 and how would I go about answering the question?

Put the "x" value you got in question 1 on the left side and see what happens. Unfortunately, I don't get that equal to 0 for either your value or mine!

 

[ehild]

I think the equation in the second question should be 2x² + 11x - 35 = 0.

ehild

 

[Mark44]

Does the triangle happen to be a right triangle? If it is, that would be good to know. If not, that would be good to know, too.

 

[HallsofIvy]

If this is were a right triangle, it would be easy to solve for x. And with that value of x, the area would NOT be 10. This cannot be a right triangle.