Solve sin(x-y) for x and y in [0,pi/2] and [pi/2,pi]"

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Homework Help Overview

The discussion revolves around interpreting the problem statement involving the function sin(x-y) with specified ranges for x and y. Participants express confusion regarding the notation and the intent behind the problem.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the meaning of the notation used in the problem, with some suggesting that the phrasing may be unclear or non-standard. There is discussion about whether the problem is asking to solve an equation or to analyze the function itself.

Discussion Status

The conversation reflects a lack of clarity regarding the problem's wording, with multiple interpretations being explored. Some participants have suggested alternative approaches to rewriting the function, but no consensus has been reached on the intended task.

Contextual Notes

Participants note that the original problem statement appears to be ambiguous, leading to confusion about the requirements for solving or analyzing the function sin(x-y).

Gamma
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Solve sin(x-y) when x= [0, pi/2], y=[pi/2, pi].

I am just not familier with the notations.

Does the above mean that I need to find the value of sin (x-y), for (x,y)= (0, pi/2) and (pi/2, pi)?

Why would they write x and y like this??
Thanks.

Gamma
 
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I haven't the slightest idea of what they have meant. The notation, if not meaningless, is at the very least obscure and non-standard.
 
What, exactly, is the wording of the problem? You can solve an equation or, more generally, a "problem" but you can't "solve" a function.
"Solve sin(x-y)" makes no sense. Does the problem ask you, possibly to solve "sin(x-y)= 0" or to find maximum and minimum values for the function?
 
Thanks guys for the replies.

This is exactly the wording of the problem.

I do felt the same way as you felt. Meaningless question. Only way I would do this is to write sin(x-y)= sinx cosy - cosx siny and substitue values.

Thanks,

Gamma.
 

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