Solve Stiffness Question: Work to Change Spring Length

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SUMMARY

The discussion focuses on calculating the work required to change the length of a spring from 8 cm to 12 cm, given a relaxed length of 6 cm and a stiffness of 150 N/m. The formula used is 1/2 Ks,f^2 - 1/2 Ks,i^2, where Ks,f represents the final spring constant and Ks,i represents the initial spring constant. The calculated work is 0.24 N/m, confirming that the work done is positive, indicating energy is required to stretch the spring.

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Homework Statement



A spring has a relaxed length of 6 cm and a stiffness of 150 N/m. How much work must you do to change its length from 8 cm to 12 cm?


Homework Equations



1/2Ks,f - 1/2Ks,i

The Attempt at a Solution



1/2 Ks,f^2 - 1/2 Ks,i ^2
1/2 (150)(0.06m)^2 - 1/2(150)(0.02)^2
=0.24 N/m

Am i right or is it supposed to be a negative value?
 
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Looks good to me! Definitely positive.
 
Alright thanks
 

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