Solve Tension Problem: 1000kg Mass at 1m/s^2

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Homework Help Overview

The discussion revolves around calculating the tension in a rope required to lift a 1000 kg mass with an acceleration of 1 m/s². The subject area pertains to dynamics and the application of Newton's second law of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore two potential equations for tension, questioning the validity of each approach. There is discussion about the implications of Newton's second law and the relationship between force, mass, and acceleration.

Discussion Status

The conversation is ongoing, with participants expressing uncertainty about the correct approach to the problem. Some guidance has been offered regarding the interpretation of Newton's second law, but no consensus has been reached on the correct calculation of tension.

Contextual Notes

Participants are considering the effects of gravitational force and net force in their calculations. There is a mention of the need for clarity on the definitions and relationships involved in the problem.

Big-J
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Homework Statement


Tension on the rope to pull a 1000kg mass up at 1m/s^2

Homework Equations


F=ma

The Attempt at a Solution


I'm not sure. It's either
A. T=ma
T=1000(1)=1000 N

or
B. T-mg=ma
T-(1000)(10)=(1000)(1)
T=11000N

Thanks.
 
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Big-J said:

Homework Statement


Tension on the rope to pull a 1000kg mass up at 1m/s^2

Homework Equations


F=ma

The Attempt at a Solution


I'm not sure. It's either
A. T=ma
T=1000(1)=1000 N

or
B. T-mg=ma
T-(1000)(10)=(1000)(1)
T=11000N

Thanks.
What is Newton's 2nd law telling you?
 
That the acceleration of an object is directly related to force and inversely related to mass. Basically F=ma I guess.
 
Big-J said:
That the acceleration of an object is directly related to force and inversely related to mass. Basically F=ma I guess.
directly related to what force?
 
Net force. I think it's option B that I did in my first post.
 
Big-J said:
Net force. I think it's option B that I did in my first post.

Yes, great.
 
Thanks for the help. Much appreciated.
 

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