Solve the conditional probability question

AI Thread Summary
The discussion focuses on a conditional probability question, specifically part c of the problem. The user seeks clarification on the correctness of their second approach to solving the question. After some confusion, they conclude that the correct solution is P(B/A') = 3/5. The conversation highlights the complexities and nuances involved in understanding conditional probability. Ultimately, the user expresses relief upon arriving at the correct answer.
chwala
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Homework Statement
see attached problem below;
Relevant Equations
conditional probability
My question is on part ##c## of the problem.
Kindly see attached question,...is the second approach correct?

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my attempt...why is the second approach wrong for question ##c##?or is it also correct?
 
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i got a little mixed up, but that's the beauty of maths ...the correct solution is
## P(B/A^{'})##=##\frac {3}{5}##
 
i think its now clear...phew!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
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