Let f(n) be of the form F(1) = 0.999999 F(2) = 0.9999999 F(3) = 0.99999999 Etc(adsbygoogle = window.adsbygoogle || []).push({});

For arbitrary N >= 1

Let g(n) = f(n)^2

G(1) and g(2) end in 8

By linear relation all g(n) end in 8

Assume 0.999... = 1

0.999... X 0.999... must end in 8 per (4)

1 x 1 does not end in 8

By (5),(6),(7), contradiction

Therefore 0.999... = 1 is a contradiction

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# B Solve this math?

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