Solve Time for Tank Filling with 2 Pipes

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SUMMARY

The problem involves determining the time it takes for two pipes to fill a tank, where the larger pipe fills it 5 hours faster than the smaller pipe. The equations derived from the problem are A + B = 6 and A = B + 5. The correct approach leads to the quadratic equation a² - 7a - 30 = 0, which can be solved to find the individual filling times for each pipe. The solution confirms that the larger pipe takes 10 hours and the smaller pipe takes 15 hours to fill the tank alone.

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Homework Statement



"A tank can be filled in 6 hours using 2 pipes. The larger pipe alone would fill it 5 hours sooner than the smaller pipe alone. How long would each pipe alone take?"

Homework Equations



I know it involves a quadratic not sure on the rest... I can't see how to do with a quadratic i mean.

The Attempt at a Solution


assume a is the big pipe and b is the small
A+B=6
A=B+5 solved them to get a=11/2hours and b=1/2, i can see that's not right. i said that a was the bigger one and my answer says that its not?
 
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pat666 said:

Homework Statement



"A tank can be filled in 6 hours using 2 pipes. The larger pipe alone would fill it 5 hours sooner than the smaller pipe alone. How long would each pipe alone take?"

Homework Equations



I know it involves a quadratic not sure on the rest... I can't see how to do with a quadratic i mean.

The Attempt at a Solution


assume a is the big pipe and b is the small
A+B=6
A=B+5 solved them to get a=11/2hours and b=1/2, i can see that's not right. i said that a was the bigger one and my answer says that its not?


This website may help you

http://www.algebra.com/algebra/home...ems/HOW-TO-Solve-Rate-of-Work-Problems.lesson


So using the the equation form the website you get

1/a + 1/a+5 = 1/6

This simplifies to

(2a+5)/a(a+5) = 1/6

which simplifies down to the quadratic a^2 – 7a -30 = 0
 
ok thanks
 

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