Helium tank filling parts to a specific pressure?

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SUMMARY

The discussion centers on calculating the volume of helium required to fill parts to a gage pressure of 0.5 bar, given an initial tank volume of 8000 cubic feet at 1 atm pressure. The user initially miscalculates the volume per part as 0.025 cubic feet, failing to account for the difference between gage and absolute pressure. The correct approach requires using absolute pressure, which is 1.5 bar (1 bar atmospheric pressure plus 0.5 bar gage pressure), to determine the necessary helium volume for each part.

PREREQUISITES
  • Understanding of gage pressure versus absolute pressure
  • Basic knowledge of gas laws and volume calculations
  • Familiarity with units of measurement (cubic feet, bar)
  • Concept of compressible fluids and their behavior under pressure
NEXT STEPS
  • Study the Ideal Gas Law and its applications in pressure-volume calculations
  • Learn about the differences between gage pressure and absolute pressure in practical scenarios
  • Research methods for calculating gas volumes under varying pressure conditions
  • Explore the implications of temperature on gas volume and pressure relationships
USEFUL FOR

This discussion is beneficial for engineers, physicists, and students involved in fluid mechanics, particularly those working with gas systems and pressure calculations.

rothrj
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Homework Statement


I have a tank that has 8000 cubic feet of helium in it. I have parts I'm filling to a gage pressure of 0.5 bar. The parts have a volume of 0.05ft^3. How many cubic feet of helium are in each part? Temperature is constant.

Homework Equations


I'm not sure if I'm missing any important variables...


The Attempt at a Solution


I figured it would be 0.05ft^3 * 0.5 bar = 0.025 cubic feet per part, but I'm not sure?

Any help? (I'm a rookie)
 
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Please note that the parts are being filled "to a gage pressure of 0.5 bar" and recognize the significance of gage pressure as opposed to absolute pressure.

Also is the He gas in the 8000 ft3 tank at 1 atm pressure? If so, one has to compress the He from an initial pressure to the higher pressure in the part.
 
So do I use absolute pressure instead of gage pressure? So 1.5 bar instead of 0.5 bar?

The 8000 ft^3 is the amount of He inside the tank at 1 bar not the size of the tank. I'm not sure what the size of the tank is.
 

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