Solve Torque Problem: 1.42M at 41.6 cm?

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SUMMARY

The problem involves determining the position to hang a mass of 1.42M on an asymmetrical ruler balanced at the 40.9 cm mark, with another mass M hung at the 100 cm mark. The correct torque equation is established as 1.42Mg(40.9 - x) = Mg(100 - 40.9), leading to the solution x ≈ 41.6 cm. However, an incorrect approach yields a negative value of x ≈ -0.72 cm, indicating a misunderstanding of the torque balance principle. The discrepancy highlights the importance of correctly applying torque equations in equilibrium problems.

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Homework Statement



Suppose the ruler in procedure 2 is asymetrical, and it is balanced at the 40.9 cm mark (at the center of mass). Now, mass M is hung on the ruler at the 100 cm mark. Where must you hang mass 1.42M so the system remains in equilibrium?
At the ... cm mark

Homework Equations



Torque equations...

The Attempt at a Solution



I think it goes this way...

1.42Mg(x) = Mg(100 - 40.9) where x is the distance from the 0 cm mark

Then, I get x ≈ 41.6 cm, but it's marked incorrect.
 
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Wait. It's..

1.42Mg(40.9 - x) = Mg(100 - 40.9)

Then, I obtain negative value, which is around...

x ≈ -0.720
 
What is a difference between x = 41.6 cm and the negative value -0.72 cm? There should be a difference between them.
 

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