Solve Transmission Losses: 50kW @ 230V, PF 0.6 Lagging

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Homework Help Overview

The discussion revolves around calculating transmission losses in electrical systems, specifically focusing on a scenario where a consumer demands 50kW at 230V with a power factor of 0.6 lagging. Participants are exploring the implications of resistance in the supply system and the relationship between real and apparent power.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of power factor to relate real power to apparent power and explore the power triangle. There are attempts to derive the necessary current and power loss using various formulas, including P=VI and P loss=I²R. Some participants also share their struggles with applying these concepts correctly.

Discussion Status

Some participants have made progress in understanding the calculations required for transmission loss, while others are still grappling with the concepts and formulas. There is an ongoing exchange of ideas and methods, with no explicit consensus reached yet.

Contextual Notes

Participants express varying levels of familiarity with the subject matter, with some indicating a lack of recent experience in power engineering concepts. There are also indications of emotional stress related to the difficulty of the problems being discussed.

SGL18
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I need help with this tutorial question I cannot solve!

a consumer demands 50kW at an effective voltage of 230V. supply system can be represented by a 0.1ohm resistance. Find the transmission losses in the event of the load being supplied with a power factor of 0.6 lagging.

I know the answer works out to be 13.13kW, but can't figure out the solution!
 
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Welcome to PF!

Hi SGL18! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
i've used the power factor=real power/apparent power (P/S) and from the power triangle i can get the real, reactive and apparent power. Can also get the impedance angle from the power factor using inverse cos function! (cos-1 0.6 = 53.13) and i know other formulas such as real power=p=V.I.cos (angle) but I'm just not sure how to put it together to get transmission loss!?
 
i Just mananged to solve this using Apparent power instead of real power! P=IV so I=P/V or rather I=S/V then P loss= I (squared)R! Thanks for replying anyway tiny-tim! just started a new power engineering class soe rest assured I'll have plenty more questions! :)
 
Hi SGL18 (and/or anyone else who reads this),

I have a similar question but can't seem to work it out from what you've posted.

Question:

A 6.35kV single phase transmission line has a series resistance of 0.01 ohms supplies a 2MW load of 0.9 lagging power factor. Find the power loss in the tansmission line.

Ans: 1.22kW

I know its not particularly difficult but I have tried everything I can and am close to suicide :/

Please help.
 
Welcome to PF!

Hi MBgigs! Welcome to PF! :wink:

Show us what you've done so far. :smile:
 
Hi and thanks for replying,

Well I figured find the Power and subtract the given power of 2MW. P = VI* so I need I. Therefore V = IR or IZ.

6350 = (0.01)(I)

I = 635000 (Already I see something is wrong)

I then subbed in for P = VI* and get a ridiculous figure not worth mentioning. I've thrown away (or recycled :) ) my scrap paper working which I won't do from now on but I've tried many other methods using the many available formula's but I am not getting anywhere.

Its been 3 years since I've done anything like this and I've jumped right into the deep end as this is just the basics for 3 phase power.

MBgigs
 
Hi MBgigs! :smile:
MBgigs said:
A 6.35kV single phase transmission line has a series resistance of 0.01 ohms supplies a 2MW load of 0.9 lagging power factor. Find the power loss in the tansmission line.

Ans: 1.22kW
MBgigs said:
Well I figured find the Power and subtract the given power of 2MW. P = VI* so I need I. Therefore V = IR or IZ.

6350 = (0.01)(I)

Oh I see, you're trying to find I from V and R. :redface:

No, you must find I from V and W (and then use power loss = I2R, as SGL18 did) …

what do you get? :smile:
 
I gave that a go but guess I don't know what to do next:

2000000 = (6350)(I)

I = 314.96A

314.96^2 x 0.01 = 992W
 
  • #10
MBgigs said:
I gave that a go but guess I don't know what to do next:

2000000 = (6350)(I)

What about the power factor? :wink:
 
  • #11
2000000 / 6350 x 0.9 = 349.96I

349.96^2 x 0.01 = 1.224kW (1.2kW) :)

Thanks again for your help. I may be in serious trouble this year :/

All the best.
 

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