Solve Trigonometric Problem for Dynamics: 4th Hint Equation

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SUMMARY

The discussion focuses on solving a trigonometric problem related to dynamics, specifically addressing the equation involving the relationship between velocity, radius, and angular velocity. The key equation presented is \vec{v}\cdot\hat{n}_{AC}=r_{AC}\omega_{AC}\to{v}_{BC}=\frac{r_{AC}\omega_{AC}}{\hat{r}_{BC}\cdot\hat{n}_{AC}}. The user is experiencing issues with visualizing certain variables in their equations, which are critical for passing their dynamics course. The problem is linked to a previous discussion on Physics Forums.

PREREQUISITES
  • Understanding of vector notation in physics
  • Familiarity with angular velocity and its applications
  • Knowledge of trigonometric functions and their relationships
  • Basic principles of dynamics and motion
NEXT STEPS
  • Review the derivation of the equation \vec{v}\cdot\hat{n}_{AC}=r_{AC}\omega_{AC} in dynamics
  • Study the concept of unit vectors and their role in vector equations
  • Explore the implications of angular velocity in rotational dynamics
  • Investigate common issues with rendering equations in LaTeX or similar tools
USEFUL FOR

This discussion is beneficial for students studying dynamics, particularly those struggling with trigonometric applications in physics, as well as educators looking to clarify these concepts for their students.

manongistong
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This problem is same as the problem on this link https://www.physicsforums.com/threads/trigonometric-problem.76696/ .

I would like to ask the number 4 hint which is "4) We therefore have, for example the equality: " the equations can't be seen on my pc as it will only outputs this
\vec{v}\cdot\hat{n}_{AC}=r_{AC}\omega_{AC}\to{v}_{BC}\hat{r}_{BC}\cdot\hat{n}_{AC}}=r_{AC}\omega_{AC}\to{v}_{BC}=\frac{r_{AC}\omega_{AC}}{\hat{r}_{BC}\cdot\hat{n}_ .

The others variables are working okay aside from the said variables/equation.

This is one of the problems I need to solve for passing dynamics. Thanks in advance.
 
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$${\vec{v}\cdot\hat{n}_{AC}=r_{AC}\omega_{AC}\ \to\ \\ {v}_{BC}\hat{r}_{BC}\cdot\hat{n}_{AC}}=
r_{AC}\omega_{AC}\ \to\ \\ {v}_{BC}=\frac{r_{AC}\;\omega_{AC}} {\hat{r}_{BC}\cdot\hat{n}_{AC} }.$$
 
BvU said:
$${\vec{v}\cdot\hat{n}_{AC}=r_{AC}\omega_{AC}\ \to\ \\ {v}_{BC}\hat{r}_{BC}\cdot\hat{n}_{AC}}=
r_{AC}\omega_{AC}\ \to\ \\ {v}_{BC}=\frac{r_{AC}\;\omega_{AC}} {\hat{r}_{BC}\cdot\hat{n}_{AC} }.$$

THANK YOU SIR!
 

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