Solve Velocity 2D Question: Find Initial Velocity

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SUMMARY

The discussion centers on calculating the initial velocity of a long jumper based on his horizontal speed at the peak of his jump. The jumper is moving at 6.5 m/s horizontally and has a center of mass 1.1 meters above the launch point. The key equation used is Vx = Vox + ax*t, where it is established that horizontal acceleration is zero due to the absence of forces acting in that direction. Therefore, the initial horizontal velocity (Vox) must equal the final horizontal velocity (Vx) of 6.5 m/s.

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Homework Statement



If a long jumper at the top of his trajectory is moving at 6.5 m/s (horizontally) and his centre of mass is 1.1m abover where it was when he launched into the jump, how fast must he have been moving when he launched?


Homework Equations




Vx = Vox + ax*t

The Attempt at a Solution



In all texts i look at they say that the initial velocity should be the same as final velocity in the x-axis but that isn't the correct answer for the question in the text.

Thanks for any help.
 
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Ask yourself this:

Is there a force in the horizontal direction that could cause an acceleration or deceleration on the jumper?

If yes: A force is exerted on the jumper in the horizontal direction thus giving him an acceleration (either forward or backward) thus changing the speed.

If no: No force is exerted on the jumper in the horizontal direction, so the acceleratoin in the horizontal direction is 0, so the horizontal speed does not change.
 

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