Solve Volume of Reactant H2SO4 for MgCO3 Reaction

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Discussion Overview

The discussion revolves around a chemistry homework problem involving the reaction between sulfuric acid (H2SO4) and magnesium carbonate (MgCO3), focusing on determining the volume of sulfuric acid used based on the mass increase of a sodium hydroxide (NaOH) solution after carbon dioxide (CO2) is passed through it. The scope includes stoichiometry and chemical reactions.

Discussion Character

  • Homework-related
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant outlines the stoichiometric relationships in the reactions, suggesting that the increase in mass of the NaOH solution is due to the CO2 produced from the reaction of H2SO4 with MgCO3.
  • Another participant challenges the interpretation of the mass increase, asserting that the weight increase is due to the absorption of CO2 by the NaOH solution.
  • Further clarification is sought regarding the source of the 15g increase, with some participants emphasizing the role of CO2 in the NaOH solution.
  • One participant suggests that NaOH is irrelevant to the calculation and that the mass increase should be directly related to the CO2 evolved from the first reaction.
  • A later reply indicates that the final understanding of the problem has been reached, confirming that the 15g increase corresponds to the CO2 produced.

Areas of Agreement / Disagreement

Participants express differing views on the role of NaOH in the problem, with some asserting it is crucial for understanding the mass increase, while others argue it is not necessary for solving the problem. The discussion remains unresolved regarding the correct interpretation of the mass increase and its implications for the stoichiometry involved.

Contextual Notes

There are unresolved assumptions regarding the interpretation of the mass increase and the role of NaOH in the reactions. The discussion reflects varying levels of understanding of the chemical processes involved.

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Homework Statement


A certain volume of a solution of 0.800M sulfuric acid was added to solid magnesium carbonate, and the carbon dioxide evolved was passed through concentrated sodium hydoxide solution. When the reaction had ceased, the mass of this solution was found to have increased by 15.0g

What volume of sulfuric acid must have been added?




Homework Equations


Basic stoichiometry


The Attempt at a Solution


H2SO4 + MgCO3 -> MgSO4 + H2O + CO2
CO2 + NaOH -> NaHCO3

Hence
H2SO4 + MgCO3 -> MgSO4 + H2O + NaHCO3

The extra weight comes from NaOH. Since the weight of the products had increased by 15g it must be due to NaOH. It comes out to .375 moles of NaOH.

Since the mole ratio for every molecule is 1, there should be .375 moles of H2SO4 added. There are 0.8 moles of H2SO4 per litre so .375/.8=.47L or 470ml of H2SO4 but the answer at the back of the book suggest something else. I don’t know where I could have made my mistake.
 
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pivoxa15 said:
...and the carbon dioxide evolved was passed through concentrated sodium hydoxide solution. When the reaction had ceased, the mass of this solution was found to have increased by 15.0g


The extra weight comes from NaOH. Since the weight of the products had increased by 15g it must be due to NaOH. It comes out to .375 moles of NaOH.
I think you've misunderstood the question. CO2 is passed into a solution containing NaOH. The mass of this solution increases as a result of passing CO2 through it.
 
Gokul43201 said:
I think you've misunderstood the question. CO2 is passed into a solution containing NaOH. The mass of this solution increases as a result of passing CO2 through it.


So the product CO2 is passed into a solution containing NaOH?

Or you are saying CO2 is in the reactants?

Could you possibly who what you think is happening with a chemical formula? Where did the extra 15g come from?
 
Mass of the NaOH solution increased when the carbon dioxide was absorbed by this solution.

Carbon dioxide is produced in the first reaction (acid+carbonate) and consumed in the second reaction (separate solution of NaOH).

Hopefully it is clear now.
 
Borek said:
Mass of the NaOH solution increased when the carbon dioxide was absorbed by this solution.

Carbon dioxide is produced in the first reaction (acid+carbonate) and consumed in the second reaction (separate solution of NaOH).

Hopefully it is clear now.

Borek
--
General Chemistry Software
www.pH-meter.info/pH-electrode

Does this mean I was correct?

H2SO4 + MgCO3 -> MgSO4 + H2O + CO2
CO2 + NaOH -> NaHCO3

Hence
H2SO4 + MgCO3 -> MgSO4 + H2O + NaHCO3

So the answers at the back of the book were wrong?
 
Forget about NaOH, it doesn't play any role here. NaOH solution part of the question is just a way of telling you what was the mass of the CO2 evolved. Insert this information into first reaction equation and you will be done.

Looks to me like 426 is a correct answer. EBAS rulez ;)


EBAS - equation balancer and stoichiometry calculator
 
pivoxa15 said:
I don't understand. There is an increase in weight of 15g. Where did 15g come from if not from NaOH?
Increase in the weight of what?

(weight of NaOH solution after passing CO2) - (weight of NaOH before passing CO2) = 15g.

Clear now?
 
Gokul43201 said:
I think you've misunderstood the question. CO2 is passed into a solution containing NaOH. The mass of this solution increases as a result of passing CO2 through it.

Gokul43201 said:
Increase in the weight of what?

(weight of NaOH solution after passing CO2) - (weight of NaOH before passing CO2) = 15g.

Clear now?

Borek said:
Forget about NaOH, it doesn't play any role here. NaOH solution part of the question is just a way of telling you what was the mass of the CO2 evolved. Insert this information into first reaction equation and you will be done.

Looks to me like 426 is a correct answer. EBAS rulez ;)

Borek
--
EBAS - equation balancer and stoichiometry calculator
www.pH-meter.info


Now it's clear. The solution in that final sentence in the question was pointing to the solution containing NaOH. The 15g was the CO2 from the first reaction. It too some time for this question but I finally understood. Thanks.
 

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