Solve Wave Motion Question HRW 8 Ch 16 Q19

[eptheta]

From HRW 8 Ch 16 Q19
http://img684.imageshack.us/img684/8947/82287578.jpg

What i did:
I resolved the components of tension is each string (T cosX and T sin X) and found X to be 19.47 degrees (sin inverse of [0.25m/0.75 m]). Then i got the value of T as 20.79 N. The Tension in the middle(between A and B) i called T2 and got it as 6.93 N [T sinX= T2]
Then, mass per unit length was found out to be 0.01kg/AB(1.5m) = 6.67x10^-3 kg/m
using the formula v= root of[T/mass per unit length], v= 32.2 m/s
The answer at the back of the book says 32.9 m/s .
Can anyone help me out here ?
Thanks

 

[ideasrule]

Probably just a rounding error on the book's part.

 

[kerimek]

I would first commend you for your thorough approach in solving this wave motion question. Your method of resolving the components of tension and finding the angle and tension values is correct. However, there may be small errors in rounding off or calculation that could result in a slight difference in the final answer.

To verify your answer, I would recommend double-checking your calculations and also checking for any conversion errors between units (such as meters to centimeters or kilograms to grams). It is also possible that the book may have used slightly different values for the given parameters, resulting in a slightly different answer.

In any scientific calculation, it is important to be as precise as possible and to check for any potential sources of error. I would suggest reviewing your steps and calculations and making any necessary corrections to arrive at the correct answer. If you are still unsure, you could also consult with a colleague or professor for further clarification.