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**Problem statement, equations, and work done:**

__In quantum mechanics, there is a relation between momentum and wavelength and between energy and frequency. These are:__

##p=\hbar k = \frac{h}{\lambda}##

##E = hf = \hbar \omega##

__A wave with an amplitude of 10cm is traveling on a string in the +x direction. The distance between wave crests (tops of oscillations) is 0.5 meters and the string oscillates up and down with a period of 0.10 seconds.__

[1] Calculate the wavelength, write the equation for the wave and calculate the wave speed.

##T=0.1 s##

##f = 10 Hz##

##\lambda = 0.5 m##

##A = 10 cm##

##k = \frac{2\pi}{\lambda} = 12.566##

##v = \frac{\lambda}{T} = 5 m/s##

##\omega = 2\pi f = 62.8 rad/sec##

##y(x,t) = A sin(kx - \omega t) = 10 sin(12.566x – 62.8t)##

[2] If the tension in the string is 0.01N, determine the mass per unit length of the string.

##F_t = \mu v^2 → \mu = \frac{F_T}{v^2} = \frac{0.01 N}{(5 m/s)^2} = 0.0004 kg/m##

[3] Use the quantum relations above to substitute momentum and energy for k and ω in the wave equation,; make sure to put the constant in the right places.

##p = \hbar k = \frac{h}{\lambda}##

##E = h f = \hbar \omega##

##k = \frac{p}{\hbar} = \frac{h}{\lambda \hbar}##

##\omega = \frac{E}{\hbar} = \frac{h}{f \hbar}##

##Asin(kx-\omega t) = A sin (\frac{px}{\hbar} - \frac{Et}{\hbar}) = Asin (\frac{hx}{\lambda \hbar} - \frac{ht}{f \hbar})##

[4] Show that kx-ωt is invariant under the Lorentz transformation. That is, with the E and p substitutions, show that, for an observer moving in the direction of wave travel, transforming x,t,E and p produces the same expression as in the original frame. It is helpful to think of vectors and dot products here.

OK this is where I am stuck.

[5] Waves carry energy from place to place. To calculate the energy density and power of a wave, start with Power = F•v. Using the note posted to the Canvas Syllabus on the speed of a wave on a string, show that the power is equal to:

##P = F_y \cdot v_y = -F_T tan(\theta) \cdot \frac{\partial y}{\partial t}##

Next, use:

##tan(\theta) = \frac{\partial y}{\partial t}##

to get:

##P = -F_T \frac{\partial y}{\partial x} \frac{\partial y}{\partial t}##

Given y = Asin(kx-ωt), calculate the two partial derivatives and write the full expression for the power. Eliminate FT using v2 = FT/μ and substitute for one of the velocity terms the correct combination of wave parameters ω and k.

Finally for the power, calculate the average power during one cycle by calculating the average of cosine squared over one period.

##f_{average} = <f> = \frac{1}{b-a} \int_a^b f(x) dx##

##<cos^2 (\theta)> = \frac{1}{2\pi} \int 0^{2\pi} cos^2(\theta) d\theta##

The graph attached may be of help in determining that average value.

**[6]**Lastly, to get the energy density, use the power as the energy delivered per unit time, so E(Δt) = P Δt and the energy density will be the energy per unit length of string , so Energy density u = E(Δt)/Δx. Carry out these steps to get an expression for the energy density of a wave on a string.