- #1
isolet
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Homework Statement
x<1
Homework Equations
∬_(z<1)▒z*dx*dy/〖(1-z^**x)〗^2
Solve x<1 Homework Problem: ∬_(z<1)▒z*dx*dy/〖(1-z^**x)〗^2
- Thread starter isolet
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Homework Help Overview
The problem involves a double integral with the expression ∬_(z<1)▒z*dx*dy/〖(1-z^**x)〗^2, where the variable z is mentioned alongside x and y. The context suggests a focus on mathematical reasoning and interpretation of the integral's setup.
Discussion Character
- Mixed
Approaches and Questions Raised
- Participants are attempting to clarify the meaning of the variables involved, particularly the relationship between z, x, and y. There are questions regarding the notation used, such as the double integral bounds and the peculiar symbol "^**". Some participants express confusion about the integrand and the overall setup of the problem.
Discussion Status
The discussion is ongoing, with participants seeking clarification on the problem's formulation. Some guidance has been offered regarding the need for clearer notation and a better understanding of the variables involved. There is no explicit consensus on the interpretation of the integral or the variables at this time.
Contextual Notes
There are constraints related to the clarity of the problem statement, including issues with language and notation. Participants have noted that the original post's formatting and symbols may hinder understanding, and there is a request for a clearer presentation of the problem.
x<1
∬_(z<1)▒z*dx*dy/〖(1-z^**x)〗^2
- #2
miniradman
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is this suppose to be a joke?
- #3
HallsofIvy
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It is not at all urgent that I solve this problem though it well may be that it is urgent for you to solve it! In any case, that template is designed as it is to make sure that you do what is required for help- show your attempt at the problem.
If you were to do that it might also help us understand what the problem is. You have a symbol that shows up only as a blob on my reader. Also you have two integral signs with lower bound "z< 1" which makes no sense. You have the peculiar notation "^**" which means nothing to me. Finally, your double integral is with respect to x and y but you have "z" in the integrand. What is z in terms of x and y?
If you were to do that it might also help us understand what the problem is. You have a symbol that shows up only as a blob on my reader. Also you have two integral signs with lower bound "z< 1" which makes no sense. You have the peculiar notation "^**" which means nothing to me. Finally, your double integral is with respect to x and y but you have "z" in the integrand. What is z in terms of x and y?
- #4
isolet
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Sorry for turkish explanation but this is problem
- #5
isolet
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https://www.physicsforums.com/attachments/41664
- #6
isolet
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first i write in computer but this is my handwrite. Computer formula is very hard to write.
- #7
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Please write the homework problem with your attempt in English. We cannot read Turkish.
If not, this thread will be deleted.
If not, this thread will be deleted.
- #8
isolet
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Last edited by a moderator:
- #9
Mark44
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Isolet,
Your image was way too large, at 2592 x 1936, and required viewers to scroll sideways and vertically to see the entire image. Images should be no larger than about 800 x 600 pixels.
Please scan your image again and repost a smaller image.
Your image was way too large, at 2592 x 1936, and required viewers to scroll sideways and vertically to see the entire image. Images should be no larger than about 800 x 600 pixels.
Please scan your image again and repost a smaller image.
- #10
isolet
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Last edited by a moderator:
- #11
Mark44
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Much better. Thanks!
- #12
isolet
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at last,ı succeed to ask to question to you 
- #13
HallsofIvy
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Well, you still haven't made it clear. As I said in my first response, your integral is with respect to x and y but you have z in your integrand. What is the relation between z and x,y? Are you working in the complex plane with z= x+ iy?
- #14
isolet
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it is clear enough and that is the question . it is the question which is asked in the doctorate programme.
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