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Solve x^2 + (-1/2x + 5)^2 = 25

  1. Apr 23, 2006 #1
    How do we solve this equation:


    x^2 + (-1/2x + 5)^2 = 25

    Thanks in advance
     
  2. jcsd
  3. Apr 23, 2006 #2

    Doc Al

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    Staff: Mentor

    Expand that squared term and you'll see that this quadratic equation simplifies nicely.
     
  4. Apr 23, 2006 #3

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    That's assuming that you mean ((-1/2)x + 5)^2 and not (-1/(2x)+ 5)^2.
     
  5. Apr 23, 2006 #4
    Thanks, then

    x^2 + (-x/2 + 5)^2 = 25

    x2 + x2/4 - 5x + 25 = 25

    5x2/4 - 5x = 0 (* 4/5)

    x2 - 4x = 0

    x(x - 4) = 0

    x = 0 or x = 4.
     
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