Solve x in tan(2x)=8cos(x)^2-cot(x) 0-90°

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SUMMARY

The equation tan(2x) = 8cos(x)^2 - cot(x) is to be solved for x in the interval of 0 to 90 degrees. The transformation of tan(2x) using the double angle formula, tan(2x) = 2tan(x)/(1-tan(x)^2), leads to the equation 2tan(x)/(1-tan(x)^2) + 1/tan(x) = 8cos(x)^2. The user encountered difficulties simplifying the equation further, particularly in combining terms effectively.

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Homework Statement


Solve for x.
tan(2x) = 8cos(x)^2 - cot(x) where x is between 0 to 90 degrees.


Homework Equations


tan(2x) = 2tan(x)/1-tan(x)^2
cot(x) = 1/tan(x)

The Attempt at a Solution



tan(2x) = 8cos(x)^2 - cot(x)
2tan(x)/1-tan(x)^2 + 1/tan(x) = 8cos(x)^2
(2tan(x)^2 + (1-tan(x)^2))/(tan(x)-tan(x)^3) = 8cos(x)^2

I am stuck at this point. Any help would be great since this is due tomorrow. Thanks.
 
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\tan{2x}=8\cos^{2}x-\cot{x}

correct? just making sure, I'm not really sure about your 2nd term.
 
Yes, you are correct.
 

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