MHB Solving 16•4^{-x}=4^x-6 Equation

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The equation 16•4^{-x}=4^x-6 can be simplified by multiplying both sides by 4^x, resulting in 16 = (4^x)^2 - 6•4^x. Substituting u = 4^x allows for easier manipulation of the equation. By setting 4^x = y, the equation can be solved for y, leading to the final solution for x as x = ln(y)/ln(4). The original poster successfully solved the equation with the provided guidance.
Petrus
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Hello MHB,
I am stuck on this equation and don't know what to do, If i take ln it does not work, any advice?
$$16•4^{-x}=4^x-6$$

Regards,
$$|\pi\rangle$$
 
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Try multiplying both sides by $4^x$. You get:
$$16 = (4^x)^2 - 6 \cdot 4^x$$
Now substitute $u = 4^x$. What do you see? :)
 
Petrus said:
Hello MHB,
I am stuck on this equation and don't know what to do, If i take ln it does not work, any advice?
$$16•4^{-x}=4^x-6$$

Regards,
$$|\pi\rangle$$

Set $4^{x}=y$, then solve for y and finally find $x = \frac{\ln y}{\ln 4}$ ...

Kind regards

$\chi$ $\sigma$
 
Hello,
Thanks for the fast respond and help from you both!:) i succed to solve it with correct answer!:)
Regards,
$$|\pi\rangle$$
 
Good morning I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...

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