Solving 2n·logn = 0.1·n² for n

[mycrafish]

2n *logn =0.1 *n^2

solve for n

please and thanks!
pozhalste e spaciba!
por favor a obrigadao

 

[scurty]

I posted this in your other topic on the other board: https://www.physicsforums.com/showthread.php?p=3819921

This forum is active enough that you will receive a response if you post it on one board, just remember that for the future!

 

[jey1234]

what level is this? high school?

 

[HallsofIvy]

Also, before anyone can "help" you, you need to show what you have tried so we will know what kind of help you need.