Solving 3 Variables with 2 Points: Can We Do It?

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Discussion Overview

The discussion revolves around the possibility of solving three variables (a, b, c) using two equations. Participants explore whether unique numerical values for all three variables can be determined from the given equations, which are presented in the context of algebraic reasoning.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant questions if it is possible to solve for three variables with only two equations.
  • Another participant argues that since the equations represent planes in three-dimensional space, they can either be parallel (no solution) or intersect along a line (infinite solutions), thus no unique solution exists.
  • A different participant demonstrates that by manipulating the equations, one can express one variable in terms of another, leading to an infinite number of solutions rather than a unique one.
  • Some participants note that there is no unique answer, suggesting that multiple solutions may be acceptable depending on the interpretation of the problem.

Areas of Agreement / Disagreement

Participants generally disagree on whether a unique solution exists. While some assert that there are infinite solutions, others clarify that the original question may not have specified the need for uniqueness.

Contextual Notes

The discussion does not clarify the assumptions regarding the nature of solutions sought (unique vs. multiple) and relies on interpretations of the equations without resolving the mathematical implications fully.

mubashirmansoor
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can we do this?

Can we solve 3 variables with 2 points? like this one

4a+2b+c=4
a+b+c=1

can we get the numerical values of all 3 variables?
 
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No. If you think of a, b, c as the x,y,z components of a point in 3 dimensional space, the 2 equations are equations of planes. The two equations will be satisfied for points where the two planes intersect. Two planes either are parallel and so don't intersect (so there is no solution) or intersect in a line (so there are an infinite number of solutions). But there cannot be a case where two planes intersect in a single point.
 
mubashirmansoor said:
4a+2b+c=4
a+b+c=1

subtract the 2nd eqn. from the 1st one and you get:
3a + b = 3
or, b = 3 - 3a

here putting different values of a, you can get different values of b. and then putting those values of a and b in either one of the original equations, you can get the value of c. thus, you can get and infinite number of solutions.

for example, if a = 1, then
b = 3-3a = 3-3*1 = 0 and
c = 1-a-b = 1-1-0 = 0
so, one solution is (a,b,c) = (1,0,0)
 
By inspection you can see there is no unique answer.
 
matt grime said:
By inspection you can see there is no unique answer.
of course we can. i was not sure whether mubashirmansoor wanted only unique answers. i thought he might have wanted a number of solutions (like the solutions of a diophantine equations). :smile:
 

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