Solving ∫(52x^7/2-66x^5/2+22^3/2)/sqrt(x) - Help Needed!

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Discussion Overview

The discussion revolves around solving the integral ∫(52x^7/2-66x^5/2+22^3/2)/sqrt(x). Participants are exploring methods for simplifying and solving the integral, focusing on calculus techniques.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant seeks guidance on the rules for solving the integral, expressing a desire for a walkthrough due to their inexperience with calculus.
  • Another participant suggests splitting the fraction and simplifying the powers of x as a method to approach the integral.
  • A further clarification is provided on how to split a fraction, indicating that (a+b+c)/d can be expressed as a/d + b/d + c/d.
  • There is a question raised about the term 22^3/2, with a suggestion that it might have been intended as 22x^{3/2} instead.
  • One participant acknowledges the suggestion and expresses gratitude.

Areas of Agreement / Disagreement

Participants generally agree on the approach of simplifying the integral, but there is uncertainty regarding the interpretation of the term 22^3/2, which remains unresolved.

Contextual Notes

There is a lack of clarity on the intended expression of the term 22^3/2, which may affect the simplification process. Additionally, the discussion does not delve into specific steps for solving the integral beyond simplification.

Who May Find This Useful

Individuals learning calculus, particularly those seeking assistance with integrals and simplification techniques.

Superposed_Cat
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Hi all, I am attempting to learn calculus in my spare time. Very short question. What rule do you use to solve ∫(52x^7/2-66x^5/2+22^3/2)/sqrt(x)? Could you please walk me through it. sorry I didn't use LaTex, I don't know it.
 
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Split up the fraction, and simplify the powers of x first.
 
arildno said:
Split up the fraction, and simplify the powers of x first.
what do you mean? I'm a total noob. How would I go about doing that?
 
Last edited:
If you have a fraction (a+b+c)/d, you may write it as a/d+b/d+c/d

Also, remember that [itex]\sqrt{x}=x^{\frac{1}{2}}[/itex]

A question:
You have a term in your numerator, 22^3/2.
Should that have been: [itex]22x^{\frac{3}{2}}[/itex]?
 
yes and thanks.
 

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