Solving a complex equation (damping/exponential-decay) like this....?

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SUMMARY

The discussion focuses on solving the equation ##e^{-0.6x}\sin{(5x)}-0.1=0##, which represents a second-order ordinary differential equation related to damped oscillations. Participants suggest numerical methods for finding roots, including bisection, regula falsi, and Newton-Raphson techniques. The Lambert W function is mentioned as a potential analytic solution, although its applicability is limited due to the equation's complexity. The context of the equation is clarified as relating to the amplitude decay in a damped spring system.

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lightlightsup
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Homework Statement
##e^{-0.6x}\sin{(5x)}-0.1=0##
Relevant Equations
https://www.desmos.com/calculator/ycgu3jt9qd
##e^{-0.6x}\sin{(5x)}-0.1=0##
I have posted my graphical solution to this problem.
But, how do I solve this numerically/mathematically without graphing it?
 
Last edited:
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What is your question? What you have is the solution to a second order ordinary differential equation with initial conditions. What are you trying to solve?
 
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lightlightsup said:
Homework Statement:: ##e^{-0.6x}\sin{(5x)}-0.1=0##
Homework Equations:: https://www.desmos.com/calculator/ycgu3jt9qd

I have posted my graphical solution to this problem.
But, how do I solve this numerically/mathematically without graphing it?
alan2 said:
What is your question?
It seems to me that the OP is trying to solve the equation shown above.

Regarding find a solution numerically, most textbooks on numerical methods list several techniques for find zeroes of equations, such as bisection, regula falsi (false position), Newton-Raphson, and others. See https://en.wikibooks.org/wiki/Numerical_Methods/Equation_Solving for examples of these techniques.

As far as analytic solutions go, there is the Lambert w function, but your equation is complicated enough that that approach might not be useful.
 
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You've both answered my question. Thank You.
 
lightlightsup said:
You've both answered my question. Thank You.
I would still like to know the statement of the problem.
 
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The "statement of the problem"
would be "Solve the equation e^{-0.6x}sin(5x)- 0.1= 0 for x". While that was not said in so many words, when a post shows an equation in "x" and asks "how do you solve this" that's pretty much implied! In your first response you seem to have the idea that this question was about differential equations. I have no idea where you got that.
 
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The ##x## above is ##t(time)##.

If you guys are wondering where this equation came from: simple damped spring oscillations, where one is solving for when a certain amplitude will be reached (or a certain percentage of a max amplitude).

The reality is that this amplitude may never actually be reached at a certain time.

But, the max amplitude envelope will be reached at that time ##t##.
So, if a damped oscillation is given by: ##x(t)=0.16e^{-0.6t}\sin{(5t)}##.
When do you reach 10% of the max amplitude (0.16 meters)?

I just wanted to confirm that I haven't yet learned the math required to solve these equations non-graphically.

Damped Oscillations Link
 
Last edited:
HallsofIvy said:
The "statement of the problem"
would be "Solve the equation e^{-0.6x}sin(5x)- 0.1= 0 for x". While that was not said in so many words, when a post shows an equation in "x" and asks "how do you solve this" that's pretty much implied! In your first response you seem to have the idea that this question was about differential equations. I have no idea where you got that.
Guess you spoke too soon, see his response above. He obviously wasn’t being asked to solve for x, it can’t be done analytically, don’t know why you would think that was the question. Of course it has everything to do with an ODE, it’s the solution to a second order equation with damping.
 
lightlightsup said:
The ##x## above is ##t(time)##.

If you guys are wondering where this equation came from: simple damped spring oscillations, where one is solving for when a certain amplitude will be reached (or a certain percentage of a max amplitude).

The reality is that this amplitude may never actually be reached at a certain time.

But, the max amplitude envelope will be reached at that time ##t##.
So, if a damped oscillation is given by: ##x(t)=0.16e^{-0.6t}\sin{(5t)}##.
When do you reach 10% of the max amplitude (0.16 meters)?

I just wanted to confirm that I haven't yet learned the math required to solve these equations non-graphically.

Damped Oscillations Link
The envelope will decay to 10% of its max when the exponential term is equal to 0.1. Then just take the natural log and solve for t.
 
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alan2 said:
Guess you spoke too soon, see his response above.
Here is is response from post #4:
lightlightsup said:
You've both answered my question. Thank You.
alan2 said:
He obviously wasn’t being asked to solve for x, it can’t be done analytically, don’t know why you would think that was the question.
He obviously was asking about how to solve the equation he wrote, either analytically or numerically. Here is what he wrote in post #1.
lightlightsup said:
Homework Statement:: ##e^{-0.6x}\sin{(5x)}-0.1=0##
But, how do I solve this numerically/mathematically without graphing it?
I made several suggestions of techniques that could be used for solving the equation numerically.
alan2 said:
Of course it has everything to do with an ODE, it’s the solution to a second order equation with damping.
But that's not the question he asked.
 

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