Solving a Derivative Problem Using the Power Rule

  • Thread starter Thread starter swears
  • Start date Start date
  • Tags Tags
    Power Power rule
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
12 replies · 3K views
swears
Messages
87
Reaction score
0
I tried this derivative problem, but the back of the book shows a different answer then what I got. Can someone explain what I'm doing wrong.

[tex]3T^5 -5T^.5 + \frac{7}{T}[/tex]

So I did this:

[tex]15T^4 - 2.5T^-.5 - 7T^-8[/tex]

It's the last part I got wrong I'm not sure why. I converted 7/T to T^-7. Is that right?
 
Physics news on Phys.org
hmm, it's not doing the exponents right, u might have too look at the code.
 
Hootenanny said:
Not quite;

[tex]\frac{7}{T} = 7T^{-1}[/tex]

Oh, does the -1 come from the 7 or T?
 
So [tex]\frac {1}{2T} = 1T^{-2}[/tex]?
 
See below message.
Hootenanny said:
It comes from the T, remember;

[tex]\frac{1}{T} = T^{-1}[/tex]
 
swears said:
So [tex]\frac {1}{2T} = 1T^{-2}[/tex]?

Nope, not quite.

[tex]\frac{1}{2T} = (2T)^{-1}[/tex]

The power applies to all terms of the denominator. However;

[tex]\frac{1}{T^2} = T^{-2}[/tex]

Does that make sense?
 
So, you basically just combine the top and bottom terms and negate the exponent.
 
Ok, well I had this other problem Maybe I can get it right here.

[tex]\frac{t^2 + t^3 -{1}}{t^4}[/tex]

I divided by T^4 and then used the power rule and I got: [tex].5T^{-.5} + .75T^{-.25} + 4T^{-5}[/tex]
 
Last edited:
I think you need to master algebra before trying calculus.

See: http://www.allaboutcircuits.com/vol_5/chpt_4/5.html