Solving a Physics Puzzle: Calculating Rope Tension

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Homework Help Overview

The discussion revolves around calculating the tension in a rope supporting a 4kg block that is accelerating downwards at 3 m/s². Participants are exploring the physics concepts related to forces, particularly tension and weight, in the context of Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply Newton's second law to find the tension in the rope, presenting two different equations and calculations. Some participants suggest drawing a free-body diagram to clarify the forces acting on the block. Others question the interpretation of net force and its direction in relation to the acceleration of the block.

Discussion Status

The discussion is active, with participants providing insights into the correct application of force equations and the importance of understanding net force. There is an ongoing exploration of the implications of different force directions and how they relate to the acceleration of the object.

Contextual Notes

Participants are grappling with the definitions of net force and the conditions under which the block is accelerating downwards. There is a mention of potential confusion regarding the signs of forces in the equations used.

JayDub
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Hey there all of you.

I am doing some studying for my final for physics and i have come across this question. I thought it was easy but it is not working that way. The question is. A 4kg block (held by a block) is accelerating down at 3 m/s/s, what is the tension of the rope?

So I am thinking to do this:
Fnet = ma
T - Fg = ma
T = ma + mg
T = 4kg(-3m/s/s) + 4kg(-9.8m/s/s)
T = 51N

So I look at the answer and it is wrong, it says it is: 27N

So now I try making the opposite end negative.

Fnet = ma
Fg - T = ma
- T = ma - mg
T = -ma + mg
T = -4kg(-3m/s/s) + 4kg(-9.8m/s/s)
T = 27N

Now I am getting the right answer. However I can not get the correct answer doing the same question the other way, so my question is what am I doing wrong? Thank you.
 
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u need to draw the Free-body Diagram. Once drawn, u with find that the tension is in an upwards direction, the weight downwards.

since it is accelerating downwards, there is a netforce in the downwards direction. thus mg-T = ma allows acceleration downwards. ( this means mg>T)

However, T-mg = ma give a netforce in the upwards direction, the object is not accelerating in the upwards direction. ( this means T>mg, but is this true ? )
 
I am sorry, I do not quite follow. Isn't the netforce up AND down?
 
Last edited:
nope, Net force = Resultant force

A net force (also known as a resultant force) is a vector produced when two or more forces act upon a single object. It is calculated by adding the force vectors acting upon the object.

for example, i put a 10N object on a table what is te net force?

the object has a weight of 10N, and by Newton 3rd law, the table exert a 10N force on the object also.

the force exerted by table is in a upwards direction and the weight is in a downwards direction.

thus the net force is [tex]F_net = 10 - 10 = 0[/tex] thus the object is not accelerating, as a netforce will cause it to accelerate
 

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