Solving a Pulley Problem in Hibbeler 11th Ed. - 13-26

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SUMMARY

The discussion focuses on solving a pulley problem from Hibbeler's "Statics and Dynamics" (11th edition), specifically problem 13-26. The problem involves a block A weighing 100 lbs moving down an incline at 5 ft/s, connected to a pulley system with block B weighing 50 lbs. The coefficient of kinetic friction is 0.2, and the incline angle is 36.9 degrees. The goal is to determine the acceleration of block A and the distance it travels before stopping, while neglecting the mass of the pulleys and cables.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of forces acting on inclined planes
  • Familiarity with pulley systems and tension calculations
  • Basic principles of friction and its coefficients
NEXT STEPS
  • Study the derivation of equations of motion for inclined planes
  • Learn about tension in pulley systems and its impact on acceleration
  • Explore the effects of friction on motion in mechanical systems
  • Review examples of similar problems in Hibbeler's "Statics and Dynamics" for practice
USEFUL FOR

Students and professionals in engineering, particularly those studying statics and dynamics, as well as anyone involved in mechanical design or analysis of pulley systems.

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Hi, I'm trying to work through a pulley problem in Hibbeler's Statics and Dynamics (11th edition). I'm working on 13-26 for those who have the text. The problem in involves a block, A of weight 100-lbs moving down an incline at 5 ft/s. It's attached to a pulley system with the first pulley stable on the roof and the rope goes through another pulley, C, below pulley A and up to the roof. Directly attached to pulley C is pulley D which has a cord running through it. One end of the cord is attached to the ground, the other has a mass, B, of weight 50-lbs. The coefficient of kinetic friction is 0.2. Here's a rough sketch, A is attached at O and the slope A is on has an angle of 36.9 degrees:

O |
| |
| |
| |
C
D
| |
| |
B |

Anyways, the problem wants to determine the acceleration of A and the distance A travels before stopping, and mass of the pulleys and cables can be neglected.

So for A, it should be \sumFx = 100 * sin(36.9) - N * 0.2 - T = massA*accelA

where N is just the normal force: 100*cos(36.9)

And I think the force's on B would be \sumFy = 50 - T = massB*accelB

Now, that leaves the lengths of cord, which should give two equations as it's two separate cords. I believe the length of the cord directly attached to A will be Sa + 2Sc = L1

But I'm unsure of the second cord so here's where I'm stuck. Also I'm not entirely sure everything else I've done is right either so if someone wouldn't mind checking that would be great.
 
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Can you provide a diagram?
 
I'll try to find one but it might be tough
 

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