Solving a Quantum Field Theory Question on Electron-Positron Pair Creation

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SUMMARY

This discussion centers on quantum field theory, specifically addressing the energy required for electron-positron pair creation and the uncertainty principle's implications. The energy needed for pair creation is calculated as 2*m(y)*c^2, where m(y) represents the relativistic mass. The uncertainty relation between energy and time is expressed as d(H)d(t) ≥ h/4π. The conversation also explores the interaction of virtual particle pairs with strong electric fields and the challenges in deriving the correct relationships between operators in quantum mechanics.

PREREQUISITES
  • Understanding of quantum field theory (QFT)
  • Familiarity with the uncertainty principle (HUP)
  • Knowledge of relativistic mass and energy equivalence (E=mc²)
  • Basic concepts of harmonic oscillators in quantum mechanics
NEXT STEPS
  • Study the derivation of the uncertainty relation in quantum mechanics
  • Explore the concept of virtual particles and their role in quantum field theory
  • Learn about the implications of strong electric fields on particle creation
  • Investigate the mathematical formalism of operator algebra in quantum mechanics
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Students and researchers in quantum mechanics, physicists interested in quantum field theory, and anyone exploring the implications of the uncertainty principle in particle physics.

Kruger
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Hello all. Seems to be an excellent forum with many experts.

I'm interested in quantum field theory. There's a question in my textbook (introduction to QM and QFT) and I'm not sure if I found the right solution and its interpretation.

Question 1: How many energy is needed to create a electron positron pair.
Answer 1: (easy) 2*m(y)*c^2 where m(y) is the relativistic mass, you know.

Question 2: Calculate the uncertainty relation between Energy and time.
Answer 2: d(H)d(t)>=h/4pi (easy)

And now there is the trickier part, a combination of these two. (the textbook derived the discret energy values of the harmonic oscillator and shows that its ground state isn't zero).

Question 11: The life time of a virtual e-e+-pair is given by the HUP and if there is a strong electric field in "empty" space with electromagnetic ground state oscillations how can the ground state oscillations create an e-e+-pair?

my Answer: I tried to calculate this: [H,N] where H is the energy of the oscillation and N the number operator. I didn't find the solution of this and got [H,N]=0 (I think not the right one). My oppinion is: The N has to raise from 0 to 1 (to create a photon in vacuum). The "N" takes the needed energy for this from HUP. After this the photon interacts with the electric field and e-e+-pair will be created for time d(t) (HUP). After this happened the pair will annihilate and the N operator will lower (N=0) and the energy is given back to "empty" space.
But as I got [H,N]=0 this can't be.

Oh, please help me. There aren't answers in this book (only questions, well the most questions are easy, but that is a difficult one).
 
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Can nobody help?
 
I don't know the answer to your problem, but try typing:

"uncertainty relation" "energy and time"

into Google. Stuff does come up that may help you.
 
Sorry, but I coudn't find what I looked for.
 
Does nobody know this?
 
Question 2: Ground state has energy what ever you want. Only energy shifts are measurable quantities.

Question 11: I don't understand what you are trying to say. It looks like non-Relativistic QM + creation of virtual particles (!?). Bad combination. The only thing I can understand is [H,N]=0. Which is true in, otherwise how would you get the energies of the harmonic oscilator?
 

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