Solving a Second Order Differential Equation: Help Needed

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SUMMARY

The discussion centers on solving the second order differential equation y'' + y(x^2 + e^x) = 0, which features both polynomial and transcendental functions as coefficients. Participants agree that analytical solutions are unlikely and suggest using series solutions as a viable approach. One user mentions utilizing NDSolve with initial conditions y(0)=1 and y'(0)=0, which provided a numerical solution. The consensus emphasizes the importance of understanding series methods, as they are not adequately covered in the referenced textbook.

PREREQUISITES
  • Understanding of second order differential equations
  • Familiarity with series solutions in differential equations
  • Experience with numerical methods, specifically NDSolve
  • Basic knowledge of polynomial and transcendental functions
NEXT STEPS
  • Study the series method for solving differential equations
  • Explore the capabilities of NDSolve in Mathematica for numerical solutions
  • Read about the theory behind series solutions in elementary differential equations textbooks
  • Investigate the relationship between initial conditions and solution behavior in differential equations
USEFUL FOR

Students and educators in mathematics, particularly those studying differential equations, as well as practitioners seeking numerical methods for solving complex differential equations.

EvLer
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Hello, not sure if it's a typo in the book but I can't work this out:

y'' + y(x^2 + e^x) = 0;

It's second order but both dependent and independent variables are present, and i am stuck.
You don't have to solve it for me entirely, a hint would be great.

Thanks in advance.
 
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The coeff are not constant and one is a polynomial and the other a transcendental function.I doubt one can find an analytical method to find the 2 solutions.

Daniel.
 
Are you saying that there's a typo in the problem?
(it's a first Diff Eq course)
 
Not necessarily. Many first course d.e. texts introduce "series solutions" but that's the only way I see to do this.
 
When in doubt guess. I ain't proud. I used NDSolve with initial conditions (just out of thin air) of y(0)=1,y'(0)=0. The results are below. I know it's not a solution but at least it's the start of a handle. :smile:

Edit: Wait a minute. That IS a solution. I mean it's not an analytically derived one. :smile:
 

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HallsofIvy said:
Not necessarily. Many first course d.e. texts introduce "series solutions" but that's the only way I see to do this.
I'm sure it's somehow deducible with series, but unfortunately the book does not discuss that anywhere, i guess i'll have to google. I wish the book or the instructor would give more of "and why do we do this?" rather than "here's how: plug and chug".

Thanks everyone.
 
Last edited:
You should use series method to solve this diff eq.
It's hard to explain the method in this tiny box(!). I suggest to check out an elemantary diff eq book and read the chapter about the series method.
 

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