Solving a Simple Derivative Problem: Understanding the Disappearance of 3x^1/2

  • Thread starter Thread starter DinosaurEgg
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary
SUMMARY

The discussion centers on the differentiation of the function \(\frac{2x-1}{\sqrt{x}}\) and the confusion surrounding the term \(3x^{1/2}\) disappearing during the differentiation process. The correct approach involves applying the quotient rule and recognizing that \(\frac{1}{\sqrt{x}} = x^{-1/2}\). The differentiation is executed using the product and chain rules, leading to the conclusion that the term \(3x^{1/2}\) is not a part of the final derivative due to its specific context in the equation.

PREREQUISITES
  • Understanding of calculus concepts such as derivatives and differentiation rules.
  • Familiarity with the quotient rule for differentiation.
  • Knowledge of the product rule and chain rule in calculus.
  • Ability to manipulate expressions involving exponents and roots.
NEXT STEPS
  • Review the quotient rule for differentiation in calculus.
  • Study the product rule and chain rule applications in various functions.
  • Practice differentiating functions involving roots and exponents.
  • Explore common pitfalls in calculus, particularly in differentiation.
USEFUL FOR

Students studying calculus, educators teaching differentiation techniques, and anyone seeking to clarify concepts related to derivatives and their applications.

DinosaurEgg
Messages
5
Reaction score
0
Here is the equation and my attempt on a dry-erase board:

bijd3b.jpg


My steps are similar to the textbook's up until I hit that 3x^1/2. Why is it disappearing with their method? It's late at night and my brain is fried; I have a feeling this will be painfully obvious to me in the morning, but in case it isn't, perhaps someone can fill me in on what I missed?
 
Physics news on Phys.org
DinosaurEgg said:
Here is the equation and my attempt on a dry-erase board:

bijd3b.jpg


My steps are similar to the textbook's up until I hit that 3x^1/2. Why is it disappearing with their method? It's late at night and my brain is fried; I have a feeling this will be painfully obvious to me in the morning, but in case it isn't, perhaps someone can fill me in on what I missed?

Recall that ##1/\sqrt{x} = x^{-1/2},## so
[tex]\frac{d}{dx} \frac{2x-1}{\sqrt{x}} = x^{-1/2}\frac{d}{dx} (2x-1)<br /> + (2x-1) \frac{d}{dx} x^{-1/2}.[/tex]
You had written ##(d/dx) x^{1/2}.##

RGV
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
Replies
3
Views
2K