a = xyz
b = xy+xz+yz
c = x + y + z
How do you solve x, y, and z?
b=(c-y-z)y + (c-y-z)z + yz = c(y+z)-y^2-zy-z^2
Solve this quadratic equation for y (or z), use both in a=xyz and hope that it has a nice solution?
It is not a quadratic equation. And it is not a "nice" solution.
I have determined that z^3-cz^2+bz-a = 0. So, if we can find the roots of the cubic function, then we have z as a function of a, b, and c. Then, it should be straightforward to find x and y in terms of a, b, and c.
But I forget how to find the roots of a cubic function.
b= c(y+z)-y^2-zy-z^2 is a quadratic equation in y (or z).
Solutions of a cubic equation
z^3-cz^2+bz-a = 0 looks very nice in my opinion.
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