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## Homework Statement

The truss is suspended by two pin joints. Each segment is 3 m wide and 4 m high. The applied force is F = 6 N. What is the force in member 10? Include the sign for tension (positive) or compression (negative).

## Homework Equations

T=rf

sum of forces = 0

## The Attempt at a Solution

On the far end joint for the Y direction

0=-6-F_seven * sin(53.13) [53.13 becaue arctan(4/3)

F_seven = -21.9344

joint on right of 10 in x direction

0=F_seven*cos(90-53.13)-F_ten

=> F_ten =-17.5 N

Please help me solve this..