The truss is suspended by two pin joints. Each segment is 3 m wide and 4 m high. The applied force is F = 6 N. What is the force in member 10? Include the sign for tension (positive) or compression (negative).
sum of forces = 0
The Attempt at a Solution
On the far end joint for the Y direction
0=-6-F_seven * sin(53.13) [53.13 becaue arctan(4/3)
F_seven = -21.9344
joint on right of 10 in x direction
=> F_ten =-17.5 N
Please help me solve this..