Solving Algebra Problems: 2.(c,i),(c,ii),(c,iii) Exam Paper

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This discussion focuses on solving algebra problems from a past exam paper, specifically Questions 2.(c,i), 2.(c,ii), and 2.(c,iii). The user initially misapplied algebraic manipulation in 2.(c,i) but was guided to rewrite the equation as rx2 - tx - h = 0 for proper quadratic solving. For 2.(c,ii), the user provided an expression of -1/6(x+6)(x-6), which was confirmed to be incorrect, with the correct formulation being h = 2x - (x2/6). The answer for 2.(c,iii) was validated as 4.96m when substituting 1.9 for height.

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pretzel1998
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Hiya.

Im having problems with Questions 2.(c,i),(c,ii) and (c,iii) question on this past exam paper. http://www.nzqa.govt.nz/nqfdocs/ncea-resource/exams/2014/91261-exm-2014.pdfCan someone check my answers and explain the questions where I face planted? Thanks!

2. (c,i). I got h/(rx-t) = x, I know this is wrong because there is 2 x's in the equation which I am pretty sure is not correct. I factored out the x and divided both sides by (rx-t), where did I go wrong?
2. (c,ii). I got -1/6(x+6)(x-6), I'm pretty confident about this one, but can someone please check it anyways? I'm often wrong when I am confident hahaha.
2. (c,iii). I got 4.96m (rounded to 2 dp), I substituted in 1.9 as the height and solved the equation found in the above question to find the width of the lane. Did I do it right?

Thanks!
 
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Hi pretzel, and welcome to MHB!

pretzel1998 said:
Hiya.

Im having problems with Questions 2.(c,i),(c,ii) and (c,iii) question on this past exam paper. http://www.nzqa.govt.nz/nqfdocs/ncea-resource/exams/2014/91261-exm-2014.pdfCan someone check my answers and explain the questions where I face planted? Thanks!

2. (c,i). I got h/(rx-t) = x, I know this is wrong because there is 2 x's in the equation which I am pretty sure is not correct. I factored out the x and divided both sides by (rx-t), where did I go wrong?
Write the equation as $\color{red}{rx^2 - tx - h = 0}$, and solve it as a quadratic in $\color{red}x$.

2. (c,ii). I got -1/6(x+6)(x-6), I'm pretty confident about this one, but can someone please check it anyways? I'm often wrong when I am confident hahaha.

I got $\color{red}{h = 2x - \dfrac{x^2}6}$. Notice that $\color{red}h$ must be 0 when $\color{red}x$ is 0 or 12.

2. (c,iii). I got 4.96m (rounded to 2 dp), I substituted in 1.9 as the height and solved the equation found in the above question to find the width of the lane. Did I do it right?
I agree with the answer 4.96m (rounded to 2 dp)

Thanks!
...
 

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