Solving an Electromagnetic Wave Problem

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The electromagnetic wave described has its direction of propagation along the z-axis, determined by the kz-ω and ωt - kz terms. The electric field components are in the x-y plane, and the propagation direction can be assumed as +z for calculations. To find the magnetic field, the relevant equation (Eq. 4) can be applied once the propagation direction is established. The Poynting vector and energy density can be calculated using equations (1) and (2), respectively. This approach allows for a systematic solution to the electromagnetic wave problem.
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Homework Statement


For an electromagnetic wave with an electric field given by
\mathbf{B}=\mathbf{i} E_o cos (kz-\omega t)+ \mathbf{j} E_o sin (\omega t - kz)
where Eo is a constant
Find
(a) its direction of propagation
(b) the magnetic field
(c) Poynting vector
(d) energy density, i.e., the amount of energy that is transmitted by the wave per unit area per unit time.

Homework Equations


(1) \mathbf{S}=\frac{1}{\mu_o}(\mathbf{E} \times \mathbf{B}) (Poynting vector)
(2) u =\frac{1}{2}\big(\epsilon_o E^2 + \frac{1}{\mu_o}B^2 \big) (energy density)
(3) \nabla\times\mathbf{E} = - \frac {\partial \mathbf{B}}{\partial t} (magnetic field)
(4) \mathbf{{\tilde{B}}}(\mathbf{r},t)=\frac{1}{c}\mathbf{\hat{k}}\times\mathbf{\tilde{E}} (magnetic field)

The Attempt at a Solution



(a) Because we have the kz-\omega and \omega t - kz terms, the direction of propagation is along the z-axis. The electric and magnetic fields are along the x-y plane. How to I know if the direction of EM wave propagation is + or - z-axis?

(b) Once I get the EM wave propagation direction, then I just use equation Eq. 4. Is that right?

(c) I just use Eq. 1, right?

(d) This is just Eq. 2, right?

Thank you very much.
 
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Wait. I think I have an answer for (a).
Hm, since
\mathbf{E}=\mathbf{i}E_o cos(kz-\omega t) + \mathbf{j}E_o sin(\omega t-kz)
we can have
\mathbf{E}=\mathbf{i}E_o cos(kz-\omega t) + \mathbf{j}E_o sin(-(kz-\omega t))
\mathbf{E}=\mathbf{i}E_o cos(kz-\omega t) - \mathbf{j}E_o sin(kz-\omega t)

After this, can I just assign an arbitrary +z propagation direction so that
\mathbf{\hat{k}}=+\mathbf{\hat{z}}

Then I can easily compute for the magnetic field \mathbf{B} Is this correct? Thanks.
 

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