A Solving an Equation: Overcoming the r's

[mhirschb]

I feel silly but I've been looking at this equation for a while and I don't fully understand the individual steps taken to go from the top line to the bottom line:

I think I am getting caught up with all the r's in the equation. I recognize that on the second line "r" describes the point at which we are evaluating the MVP, and r' is the domain of r that we're integrating over.
I'm confused because it looks like they've taken the 1/r and changed it to r' on the other side.

 

[pasmith]

The first equation obtains B_z from A_\theta bythe following steps:

• Multiply by r.
• Differentiate with respect to r.
• Divide by r.

Therefore A_\theta is obtained from B_z by reversing these steps:

• Multiply by r.
• Integrate with respect to r. This is done as a definite integral with lower limit 0, because any other choice of lower limit would make A_\theta potentially infinite at r = 0. This definite integration requires the introduction of r' as a dummy variable of integration, because it is bad practise to use r as both a limit of the integral and the dummy variable of integration.
• Divide by r.

 

[mhirschb]

The first equation obtains B_z from A_\theta bythe following steps:

• Multiply by r.
• Differentiate with respect to r.
• Divide by r.

Therefore A_\theta is obtained from B_z by reversing these steps:

• Multiply by r.
• Integrate with respect to r. This is done as a definite integral with lower limit 0, because any other choice of lower limit would make A_\theta potentially infinite at r = 0. This definite integration requires the introduction of r' as a dummy variable of integration, because it is bad practise to use r as both a limit of the integral and the dummy variable of integration.
• Divide by r.

Ah! It makes so much sense now I wanna facepalm!

Thank you for the explanation. It became clear when I needed to introduce the dummy variable r'.