# Solving an equation that resembles exact equation

1. Sep 27, 2011

### AlonsoMcLaren

If an ODE can be written in the form M(x,y)dx+N(x,y)dy=0, where M=δf/δy and N=δf/δx. Why isn't it correct to solve the ODE using the way analogous to the way solving Exact differential equations?

2. Sep 29, 2011

### LCKurtz

It is, but I think you didn't write what you meant.

If M = ∂F/∂x and N = ∂F/∂y, then the equation is exact and F(x,y) = C is its solution. But this can't happen unless ∂N/∂x =∂M/∂y, which is the test for exactness.