Solving an Equation using the Gravitational Constant

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Homework Help Overview

The discussion revolves around calculating the escape velocity of an object using the gravitational constant. Participants are exploring the steps involved in manipulating the equation and clarifying unit conversions, particularly from grams to kilograms.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the addition of 0.001 in the equation and discussing the conversion of mass from grams to kilograms. There are attempts to clarify the formula for escape velocity and the necessary steps to proceed with the calculation.

Discussion Status

The discussion is active, with participants providing insights into unit conversions and the structure of the escape velocity formula. Some guidance has been offered regarding unit cancellation and the importance of maintaining consistent units throughout the calculation.

Contextual Notes

There is an emphasis on ensuring that all values are in SI units before performing calculations, and participants are navigating the complexities of unit conversions and their implications for the problem at hand.

Thrawn
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Homework Statement


Why, in the second step of the question, is 0.001 added to the right side?

Part 2. In the equation Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m

I'm trying to calculate the escape velocity of an object, and have figured out everything up to this point. Now, I have no idea how to procede. Do I cancel things out? Do I add a number to both sides?


Homework Equations


G2.gif





The Attempt at a Solution



For the first part, I would guess that it is simply to... well I have no idea...
 
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Thrawn said:

Homework Statement


Why, in the second step of the question, is 0.001 added to the right side?
200 is multiplied by 0.001 to convert it from grams into kilograms, since there are 1000g in 1kg-- does that answer your question?
Part 2. In the equation Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m

I'm trying to calculate the escape velocity of an object, and have figured out everything up to this point. Now, I have no idea how to procede. Do I cancel things out? Do I add a number to both sides?

I don't get what you mean by this!
 
cristo said:
200 is multiplied by 0.001 to convert it from grams into kilograms, since there are 1000g in 1kg-- does that answer your question?


I don't get what you mean by this!

The formula to calculate escape velocity is:

Ve = sqrt 2(mu)/r

Where r is the distance from the denter of the object to be escaped from, and mu is the Gravitational Constant multiplied by the mass of the object to be escaped from.

All sai and done, this gives an equation of: Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m

What would be the next step in solving this?
 
You just need to check that the units cancel to give a unit of velocity (noting that N=kg m s-2), then compute the numerical answer.
 
cristo said:
You just need to check that the units cancel to give a unit of velocity (noting that N=kg m s-2), then compute the numerical answer.


So would the next step be: Ve = sqrt 2(6.6742 x 10^-11 kg m/s^2 m^2/kg^2 (12.1kg)/0.106780959m ?

If not, then what?
 
Yes, now check that the units cancel and compute the numerical answer.

Personally, I think the method of keeping the units in during the calculation is very confusing, and that you should convert everything into SI units before plugging into the equation. But ,if that's how you've been taught to answer the question, then I guess you should do it that way.
 
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