MHB Solving an exponential equation

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To solve the equation 0.3(4^0.2x) = 0.2, it can be rewritten as 4^(x/5) = 2/3. This transformation allows the use of logarithmic properties, specifically applying the logarithm to both sides to isolate the variable. The logarithmic form of the equation is log_4(2/3) = x/5, which can then be solved for x. The final step involves calculating the exact and decimal solutions, rounding the decimal to three places.
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I'm doing some optional problems in preparation for my final in two weeks in one of my classes and I'm stumped on this one in particular

Express irrational solutions in exact form and as a decimal rounded to three decimal places.

Problem: 0.3(4^0.2x) = 0.2

I won't be able to look back here for a few days so some help within the next hour or so would be nice but not required thanks in advance for the help!
 
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Re: Logarithmic Function Help Plz :(

I would begin by expressing the equation as follows:

$$4^{\frac{x}{5}}=\frac{2}{3}$$

Now, given:

$$a^b=c$$

this implies:

$$\log_a(c)=b$$

So, how can you convert the above equation from exponential to logarithmic form?
 
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