Solving an Integral: Is My Attempt Right?

[Jumpy Lee]

Homework Statement

$$\int x/2x-20)^(1/2)$$

The Attempt at a Solution

I did u sub got the $$\int (u+20)/(2u^1/2)du$$ which became (1/6)(2x-20)^(3/2) + 10(2x-20)^(1/2)

Is this right? What am i doing wrong if it is not.

 

[HallsofIvy]

Do you mean
$$\int\frac{u+20}{2u^{1/2}}du$$
If so that is the same as
$$\int [(1/2)u^{1/2}+ 10u^{-1/2}]du$$
I don't see how you would get 2x-20- since there is no x in the original integral!