Solving a•b=(a+b)^2 with no Identity for Real Numbers

  • Thread starter Thread starter Zashmar
  • Start date Start date
  • Tags Tags
    Groups
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 1K views
Zashmar
Messages
48
Reaction score
0
Show that a•b=(a+b)^2 has no identity for real numbers
Hi this is a new topic please help
Thanks
 
Physics news on Phys.org
An "identity" for an operation would be a member of the group, I, such at a•I= I•a= a. So you just need to show there is no number, I, such that (a+ I)^2= a for every a.