Solving Basic Algebra Question 1: x - (-6) = 12

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Homework Help Overview

The discussion revolves around solving a basic algebra equation, specifically x - (-6) = 12. Participants are exploring the implications of subtracting a negative number and the correct steps to isolate the variable x.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants attempt to simplify the equation by adding 6 to both sides, questioning whether this is valid when dealing with a negative number. Others suggest that the correct approach involves adding (-6) to both sides instead.

Discussion Status

Participants are actively engaging with the problem, offering different perspectives on how to approach the equation. There is a recognition of multiple methods to solve the problem, and some guidance has been provided regarding the order of operations and the handling of negative numbers.

Contextual Notes

Some participants express confusion regarding the treatment of negative numbers in the context of the equation, indicating a need for clarification on algebraic principles. The original poster mentions a discrepancy between their understanding and the textbook's explanation.

KevinMWHM
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1. x - (-6) = 12


To simplify, I want to get rid of the (-6). So wouldn't I say
2. x - (-6) +6 = 12 + 6
x = 18?



The book I'm using says to add (-6) to both sides but doesn't a neg + neg still equal a neg? I've been flawless to this point, what's confusing me?

The books answer
2. x - (-6) + (-6) = 12 - 6
x = 6
 
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-(-6) + 6 = 6 + 6
 
KevinMWHM said:
1. x - (-6) = 12


To simplify, I want to get rid of the (-6). So wouldn't I say
2. x - (-6) +6 = 12 + 6
x = 18?



The book I'm using says to add (-6) to both sides but doesn't a neg + neg still equal a neg? I've been flawless to this point, what's confusing me?
In the original equation a number is being subtracted from x. To isolate the x you need to add the same number.

If the equation was
[tex]x - 6 = 12[/tex]
you would add 6 to both sides:
[tex]x - 6 + 6 = 12 + 6[/tex]

But your equation is
[tex]x - (-6) = 12[/tex]
which still has a subtraction, so you have to add (-6) to both sides:
[tex]x - (-6) + (-6) = 12 + (-6)[/tex]

Another way to solve the equation is to first rewrite the subtraction as an addition:
[tex]\begin{aligned}<br /> x - (-6) &= 12 \\<br /> x + 6 &= 12<br /> \end{aligned}[/tex]
Now that you have an addition, you subtract 6 from both sides to isolate the x:
[tex]x + 6 - 6 = 12 - 6[/tex]

Hope this makes sense.


69
 
KevinMWHM said:
1. x - (-6) = 12


To simplify, I want to get rid of the (-6). So wouldn't I say
2. x - (-6) +6 = 12 + 6
x = 18?



The book I'm using says to add (-6) to both sides but doesn't a neg + neg still equal a neg? I've been flawless to this point, what's confusing me?

The books answer
2. x - (-6) + (-6) = 12 - 6
x = 6

Your first step is to remove the parens by resolving -(-6), THEN you substract something from both sides of the equation.
 
AC130Nav said:
Your first step is to remove the parens by resolving -(-6), THEN you substract something from both sides of the equation.
That is one way of doing the problem. You don't have to do it that way. eumyang showed how to do it following the OP's method.
 
HallsofIvy said:
That is one way of doing the problem. You don't have to do it that way. eumyang showed how to do it following the OP's method.

But, perhaps, a student should be reminded to use the algebraic hierarchy. Makes it easier to understand.
 

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