Solving C++ Logical Ops 2: Print "Special Number

[ineedhelpnow]

Write an expression that prints "Special number" if specialNum is -99, 0, or 44.

Sample program:

#include <iostream>
using namespace std;

int main() {
   int specialNum = 0;

   specialNum = 17;
   
   if (<STUDENT CODE>) {
      cout << "Special number" << endl;
   }
   else {
      cout << "Not special number" << endl;
   }

   return 0;
}

i thought it would be

(specialNum == -99) || (specialNum == 0) || (specialNum = 44)

but its not

 

[Nono713]

Write an expression that prints "Special number" if specialNum is -99, 0, or 44.

Sample program:

#include <iostream>
using namespace std;

int main() {
   int specialNum = 0;

   specialNum = 17;
   
   if (<STUDENT CODE>) {
      cout << "Special number" << endl;
   }
   else {
      cout << "Not special number" << endl;
   }

   return 0;
}

i thought it would be

(specialNum == -99) || (specialNum == 0) || (specialNum = 44)

but its not

That last condition is an assignment. You want specialNum == 44, because "specialNum = 44" is a statement that means "assign 44 to specialNum, and return that value". Thus it logically becomes true (as 44 is not zero) and you always get "special number" (and if you printed specialNum it would mysteriously always be 44.

Be careful between = and == :)

 

[ineedhelpnow]

i literally read over that piece of code i wrote like ten times and i didnt even notice that i missed a '='. thanks bacterius!