Solving Calorimetry Problem: Iron in Water

[xwhoaaax3]

okay so i understand q=mc∆T and all but this problem really has me stumped

a 12g piece of iron (80°C) has been dropped into 600g of water (25°C)

the specific heat of water is 4.184J/g°C and iron's is .44J/g°C

what is the final temperature of the two?

 

[hage567]

So you need to apply that equation for each substance. The heat lost by the iron will equal the heat gained by the water. They will both come to the same final temperature.

Try to set it up.