- #1

John Ker

- 16

- 1

## Homework Statement

A 529 g piece of copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/°C, what is the final temperature of the system [c of copper = 0.387 J/g · K]?

## Homework Equations

*q*=

*q*1 +

*q*2 +

*q*3 + ... = 0

Where q = (Tf - Ti) m c

## The Attempt at a Solution

This is the part where I am stuck, knowing how to organize the equation.

Ive gotten this so far,

529 * .387 (Tf - 89.5) = 159 * 4.18 * (Tf - 22.8) + 10(Tf - Ti)

Im not sure how the vessel comes into this.

Thanks!