# Final Temperature of Copper and Water in Insulated Vessel

• John Ker
In summary, Copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. The final temperature of the system is 0.387 J/g · K.
John Ker

## Homework Statement

A 529 g piece of copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/°C, what is the final temperature of the system [c of copper = 0.387 J/g · K]?

## Homework Equations

q = q1 + q2 + q3 + ... = 0

Where q = (Tf - Ti) m c

## The Attempt at a Solution

This is the part where I am stuck, knowing how to organize the equation.

Ive gotten this so far,

529 * .387 (Tf - 89.5) = 159 * 4.18 * (Tf - 22.8) + 10(Tf - Ti)

Im not sure how the vessel comes into this.

Thanks!

Assume initial temperature of the vessel to be that of water it contained.

Borek said:
Assume initial temperature of the vessel to be that of water it contained.

SO the fomula would become:
529 * .387 (Tf - 89.5) = 159 * 4.18 * (Tf - 22.8) + 10(Tf - 22.8)

Where I then distribute everything out and solve for Tf?
Are the signs correct on both sides, I recall seeing that one side needs to be negative, but I am not sure that is relavent here.

No, signs are not OK. As your ΔT is defined as final-initial all heats (lost and gain) should be on one side of the equation, just like you wrote in your opening post.

It is also possible to solve such problems using a different convention, one in which we combine things that get colder (lose heat) on one side of the equation and things the gain heat (get hotter) on another side, then all changes in the temperature are assumed to be positive. Mathematically it is equivalent, can be sometimes easier conceptually. The only thing that really matters is that you stick to one convention and not mix them both.

In this particular case the error would be easy to spot - solve the equation you have listed for Tf, does the result make sense?

John Ker

## 1. What is heat flow in chemistry?

Heat flow in chemistry refers to the transfer of thermal energy from one object or system to another. This can occur through conduction, convection, or radiation.

## 2. How is heat flow measured in chemistry?

Heat flow is measured in chemistry using units of joules (J) or calories (cal). It can also be measured indirectly by changes in temperature or enthalpy.

## 3. What factors affect heat flow in chemical reactions?

The rate of heat flow in chemical reactions is influenced by factors such as the temperature difference between the reactants and surroundings, the surface area of the reactants, and the presence of catalysts.

## 4. Can heat flow be reversed in a chemical reaction?

In most cases, heat flow in a chemical reaction is irreversible. However, certain reactions, such as endothermic reactions, can be reversed by changing the conditions (e.g. temperature) of the reaction.

## 5. How does heat flow play a role in thermodynamics?

Heat flow is an important concept in thermodynamics, as it is related to the transfer of energy between systems. It is a key factor in determining the spontaneity and direction of chemical reactions.

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