Solving Car Problem: Acceleration, Coasting and Deceleration

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SUMMARY

The discussion focuses on solving a physics problem involving a car's acceleration, coasting, and deceleration. The force required to accelerate a 1000 kg car at 3 m/sec² is calculated as 3000 N using the formula F=ma. After accelerating for 45 seconds, the car reaches a final velocity of 135 m/sec. During a 20-minute coast with no net forces, the car maintains this speed, and the work done during deceleration is analyzed, emphasizing the relationship between force, distance, and kinetic energy.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of kinematic equations
  • Concept of work and energy in physics
  • Familiarity with units of measurement (kg, m/sec², N)
NEXT STEPS
  • Study kinematic equations in-depth, focusing on Vf=Vo+aT
  • Explore the concept of work and energy, particularly in relation to kinetic energy
  • Learn about the implications of coasting and its effect on velocity
  • Investigate the relationship between force, mass, and acceleration in various contexts
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of motion and energy in vehicles.

ataglance05
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This problem is in various questions, so please bear with me.

Homework Statement


a) A car weighing 1000 kg is accelerated at 3 m/sec^2. What is the force required to produce that acceleration?.

b) in problem a- the car is accelerated for 45 seconds. How fast in m/sec is it going at the end of 45 sec?

c) in problem b- after the initial 45 second acceleration period, the car coasts (no net forces) for 20 minutes. ca) How fast is it going at the end of 20 minutes? How far did it go in hat 20 mintues?
cb) How much work was done on the car in that 20 minutes?
cc)At the end of the 20 minute coast period, the car is decelerated to a stop. How much work was done to bring the car to a stop?
cd)If the car took 35 seconds to stop, what was the force on the car and how far did it travel in the meters before it stopped

Homework Equations


a) F=ma
b) Vf(final velocity)= Vo(initial velocity) + a(acceleration)T(time)
c) F=ma or Vf=Vo+aT or S(distance)=volt+ 1/2(a)(T^2) or W(work)=(F)D
(D is distance)

The Attempt at a Solution


a) F=ma
F=1000kg(3 m/sec^2)
F=3000 N

b) Vf=Vo+aT
Vf=0+3 m/sec^2(45 sec)
Vf=135 m/sec

c)PLEASE HELP!
 
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ca) coasting means what about its speed? If you know how fast it was going for the 20 minutes...how far did it cover?

cb) What is the definition of work? Can you do work if F=0?

cc) What can you say about the kinetic energy of the car as it goes from 135m/s to 0m/s? Where did that energy go?

cd) Re-use the technique you used in 3a.
 
berkeman said:
ca) coasting means what about its speed? If you know how fast it was going for the 20 minutes...how far did it cover?

cb) What is the definition of work? Can you do work if F=0?

cc) What can you say about the kinetic energy of the car as it goes from 135m/s to 0m/s? Where did that energy go?

cd) Re-use the technique you used in 3a.

ca) coasting means that the speed stayed the same throughout the 20 minutes?

cb) Work is the exertion or effort directed to produce or accomplish something. I guess that one can not do work if there is no force. I still don't postulate how this answers the question.

cc) The kinetic energy stops being present? The energy just dissipated.

cd) Reusing the formula F=ma would mean that I would have to multiply 1000kg by the acceleration of the car which I really do not know what it is.

I am very perplexed!@!#!
 

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