Solving Circuits with Kirchoff's Laws

  • Thread starter Thread starter meczs
  • Start date Start date
  • Tags Tags
    Circuits Laws
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
meczs
Messages
7
Reaction score
0
http://www.pa.msu.edu/courses/1997spring/PHY232/lectures/kirchoff/examples.html"

how can you solve my circuit (that i attached) using that procedure... in that site.. i saw it last week... that's the shortest way i seen... can you help me.. thankss
 

Attachments

  • KCL.JPG
    KCL.JPG
    12.3 KB · Views: 574
Last edited by a moderator:
Physics news on Phys.org
yah i learned it... but it is the longest solution... i hate that... i want the shortest method... that i found in that site.. can you solve it using that method?

i put the answer @ my attachment

here is the solution I've learned

@node B
i1 + 12 - i3 = 0
i3 = i1 + i2 that is for eq. 1

@loop abefa
E1 + E2 -15i1 +26i2
40v + 50v -15i1 +26i2
90 + 26i2 / 15i1 eq. 2

@loop bcdeb
-E2 -E3 -26i2 -37i3
-50 -60 -26i2 -37i3
-110 -37i3 / 26i2 eq. 3

that is the my sample solution I've learnd... but it is not finish.. like i said; that is the longest solution... hoping that you understand it...

(sorry bad grammar)
 
You need to set the second two things equal to zero to make them equations. That gives you 3 equations and 3 unknowns -- just solve away. There's not really a quicker way to solve it that I know of, unless you mean using determinants to solve the simultaneous equations. In this circuit, the equations are simple enough that solving with determinants won't save you any time.