Solving Collision Question: Speed After Intersection Impact

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SUMMARY

The collision of two identical cars, each traveling at 50 km/h, results in a joint wreck that conserves linear momentum. The correct method to determine the speed after the collision involves calculating the total momentum before the impact and setting it equal to the total momentum after the impact. The initial momentum of the system is the vector sum of the two cars' momenta, which requires considering both mass and velocity. The final speed of the wreck can be calculated using the formula for momentum conservation, rather than relying solely on the Pythagorean theorem.

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I've been working on this question and I just don't know how to arrive at the correct answer!
Here's my question.

Two identical cars, each traveling at 50km/h, one traveling north and one traveling east, collide at an intersection and become locked together.
What is the speed of the joint wreck immediately after the collision?


I tried using the pythagoras theorum to attempt finding the new speed.
Root(50^2 + 50^2) but this gave me a new speed of 70.7km/h which I believe is wrong since the are moving at a faster speed.

How do I solve this question?:confused:
 
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Since the external forces that act on the system (the two cars) sum to zero, the linear momentum of the system is conserved. So you have the final total momentum of the system set equal to the initial total momentum of the system. Now you can solve for the final velocity.
 
eclipse30 said:
I tried using the pythagoras theorum to attempt finding the new speed.
Root(50^2 + 50^2) but this gave me a new speed of 70.7km/h which I believe is wrong since the are moving at a faster speed.
As hotcommodity explained, you should be adding the momentum, not just the velocities. (You can still use this calculation, but you'll have to modify it to include the mass.) When the cars are locked together, what's the total mass?
 

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