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NotaMathPerson

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The acceleration function of an object doing curvilinear motion is a = {(-0.2t)i+2j+1.5k} m/s^2, where t is in s. If its initial velocity v0 = 8i m/s, and initial position is at the origin, determine the magnitude of its velocity when t=3 s.

Badly need your help guys. Thanks!

All I see is

ax = -0.2t

ay = 4

az = 1.5

Integrating all components i have

Vx= t^2/10 m/s

Vy = 2t m/s

Vz = 1.5t m/s

@ t = 3s

I get V = 7.554 m/s

But I ignored V0 which i don't know the use of.

Badly need your help guys. Thanks!

All I see is

ax = -0.2t

ay = 4

az = 1.5

Integrating all components i have

Vx= t^2/10 m/s

Vy = 2t m/s

Vz = 1.5t m/s

@ t = 3s

I get V = 7.554 m/s

But I ignored V0 which i don't know the use of.

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