Solving DE- which approach and more importantly - why

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My end goal is to solve for [itex]G(m)[/itex] in terms of the other functions, but first I have to solve the DE :

[itex]\frac{d}{dm}[F(m) G(m)] = (\frac{d}{dm}F(m)) D(m)[/itex].

What I've done is to say (using integration by parts)

[itex]F(m) G(m) = F(m)D(m) - \int F(m) (\frac{d}{dm}D(m)) dm[/itex].

This is one method I tried. Another approach would be a separation of variables, which I tried as...

[itex]\frac{d}{dm}[F(m) G(m)] = \frac{dF}{dm} G + F \frac{dG}{dm} = \frac{dF}{dm} D[/itex]

which leads to...

[itex]\ln |F| = \int \frac{dG}{D - G} dm[/itex] and I believe that the RHS cannot be evaluated without specifying functions [itex]D[/itex] and [itex]G[/itex] (if the RHS can be evaluated without specification - please let me know...and please show me the way).

Help on understanding the correct method would be extremely appreciated.

Thanks in advance.
 
If you just need an expression for G in terms of F and D, then the first one looks more like it gets you there.

I noticed that $$\renewcommand{\dd}[2]{\frac{d #1}{d #2}}
\renewcommand{\dm}[1]{\frac{d #1}{dm}}

G\dm{F}+ F\dm{G} = D\dm{F}$$ rearranges to $$\dm{G}= \frac{D-G}{F}\dm{F}$$ ... integrate both sides wrt m ... but it's early and I havn't had my coffee yet...
 
Hi Simon, thanks for your reply.

Thanks for your suggestion, but I think I'll stick with the integration by parts method, since I have convenient expressions for [itex]F(m) (\frac{d}{dm}D(m))[/itex] that I will need to integrate.

Once again, thanks for the help.
 
Hi !
it's a separable EDO :
 
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  • Handwritten derivation: d/dm(FG) = D dF/dm, then G dF/dm + F dG/dm = D dF/dm, (D - G) dF/dm = F dG/dm, 1/F dF/dm = 1/(D - G) dG/dm, ln(F) = integral of 1/(D - G) dG/dm dm, F = exp(integral of 1/(D - G) dG/dm dm).
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