How can boundary conditions be written for a DEQ with Dirac delta?

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The discussion centers on solving a differential equation (DEQ) involving a Dirac delta function and Robin boundary conditions. The equation models a 1D diffusion system with a point scatterer affecting population distribution. Participants highlight the need for four boundary conditions due to the nature of the second-order DEQ, emphasizing the interaction between two regions divided by the point scatterer. A suggestion is made to approach the problem by treating it as two coupled DEQs, each defined on either side of the scatterer, while considering the shared boundary conditions. The conversation concludes with a hint to integrate the ODE around the scatterer to derive the appropriate boundary conditions.
rynlee
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Hi All,

so I'm trying to tackle this DEQ:

f''[x] = f[x] DiracDelta[x - a] - b,

with robin boundary conditions
f'[0] == f[0], f'[c] == f[c]

where a,b, and c are constants.

If you're curious, I'm getting this because I'm trying to treat steady state in a 1D diffusion system where I have homogenous generation along the length (b, in 1/(length-time) units), f(x) is the population distribution, and I have a point scatterer at x=a consuming population at a rate proportional to the concentration there (f(x)). i.e.
f=f(x,t)
df/dt = D*(d^2/dx^2)f + b - f*DiracDelta(x-a) = 0

I tried to take a laplace transform approach but couldn't hack it, if someone has another idea on how to approach this I'd appreciate it!

Thanks!
 
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Properly I should title this more like

"diffusion-reaction DEQ with delta reaction term in steady state with homogenous generation"
 
Rynlee,
can you see the geometrical meaning of your ODE in a small neighborhood of a? Do you understand why you have 4 BCs for a second order ODE?
 
don't I have 2 BCs in a second order DEQ?

If you stick with the original 2D problem I have 2BCs (those) and in the steady state assumption no longer need an initial conditions since I eliminate t, leaving me with the 2nd order DEQ and two robin BCs.

For a simpler problem Neumann BCs could be taken,
f'[0] == 0, f'[c]==0
But the difficulty remains.
 
You are right, I misinterpreted your statements. Hint: you have two problems, one before and one after a. Do you know how to handle them?
 
Coelum said:
You are right, I misinterpreted your statements. Hint: you have two problems, one before and one after a. Do you know how to handle them?

That's a good point, really this could be viewed as two coupled DEQs, one defined on [0,a] and the other defined on [a,c], each with a set of Robin BCs, with one of them shared (at a).

The two DEQs aren't independent though, since the BCs are Robin not Neumann. If we instead had
f'[0]=f'[a]=f'[c]=0, then I could split this into two DEQs. Since that's not the case though, the distribution on each side of a effects the other side.
 
Rynlee, you got the point: do you know how to write the BCs in a? Hint: integrate the ODE in [a-delta,a+delta] and compute the limit when delta->0.
 

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