Solving Derivative of 6x/(x2+3)2

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SUMMARY

The discussion focuses on finding the derivative of the function 6x/(x²+3)². The initial attempts at solving the derivative using multiplication and fraction methods yielded incorrect results. The correct approach involves applying the product rule and chain rule, where the function is expressed as h(x)=f(x)g(p(x)), with f(x)=6x, g(z)=z⁻², and p(x)=x²+3. The derivative is calculated using the formula h'(x)=f'(x)g(p(x))+f(x)g'(p(x))p'(x).

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Homework Statement



6x/(x2+3)2


The Attempt at a Solution


If I solve this function as a multiplication, i.e.

6x (x2+3)-2

my answer is

f ' (x)=[ (x-3)(x-1) ]/(x2+3)3

If I solve it as a fraction
f ' (x)=(v'g-g'v)/g2

I get

f ' (x)=(x2-1)/(x2+3)3


This is all so confusing. Please help me out. Thank you.
 
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Neither is correct. Show us your steps so we can see where your mistakes lie.
 
6x (x2+3)-2


Did you use the product rule followed by the chain rule?

You can consider this function as:

h(x)=f(x)g(p(x))

where:

f(x)=6x, g(z) = z-2 ,and p(x)=x2+3

Now how would you take the derivative of h(x)?

Hint: h'(x)=f'(x)g(p(x))+f(x)g'(p(x))p'(x)
 

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